1x^2+4x+40=0

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Solution for 1x^2+4x+40=0 equation: 



1x^2+4x+40=0

We add all the numbers together, and all the variables

x^2+4x+40=0

a = 1; b = 4; c = +40;
Δ = b2-4ac
Δ = 42-4·1·40
Δ = -144
Delta is less than zero, so there is no solution for the equation

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